Linear Approximation for functions with first derivative as $0$

Linear approximation around a point through Taylor series requires the first order derivative to be non-zero unless you want to get only the value at that point. However this is only true when you are extremely close to the referred point. Is there a better way to linearly approximate such a function. For example, using Taylor Series to evaluate linear approximation of the function, $f(x) = (1+x^2)^<1/2>$, yields $1$ which is really true if you are extremely close to $x=0$. Also it is not a first order approximation since its constant. Is there another way to approximate, lets say, if I know the lower and upper bounds on $x$?

• approximation
• linear-approximation

$\begingroup$ If you use 0 for the 1st order term you have a bound on the error (Lagrange's remainder). If you use something else for the 1st order term you don't know, in general. BTW, a constant is a particular case of a linear approximation $\endgroup$

$\begingroup$ There's nothing wrong with the first-order approximation being constant. It just means the function is rather flat near that point. After all, how else would you approximate a function that actually is constant? Or what about the function $x\mapsto x^+ 7$ near $x=0$? $\endgroup$

$\begingroup$ @LuisMendo sorry I didn't get the first part. the only better way I can think of is to use the middle point of my bounds and approximate there. As for the constant being a particular case of linear approximation I am not sure since using this argument a lower order polynomial is always a particular case of a higher order polynomial $\endgroup$

$\begingroup$ @MPW I can understand what you mean but I was wondering if there is another way to approximate if your margin of error is relatively large $\endgroup$

$\begingroup$ If you require linear approximation, then move the center to another point which is closer to the point at which you need to evaluate the approximation. Approximations are implicitly local approximations, which means they are only valid for small neighborhoods, not globally. $\endgroup$